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Question 24087
NEET Chemistry · Medium

Equilibrium: Ksp numeric MCQ

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Ksp numericMediumQuestion 24087

Question

For AB with Ksp=10−10K_{sp}=10^{-10}, molar solubility in pure water is:

  1. A
    10−510^{-5} M
    Correct
  2. B
    10−1010^{-10} M
  3. C
    10−210^{-2} M
  4. D
    5×10−55\times10^{-5} M

Correct answer

10−510^{-5} M

Explanation

For a 1:1 salt, s=Ksps=\sqrt{K_{sp}}.

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