Mixed Vectors & CalculusMediumQuestion 5152
Question
∫₀^π sin x dx equals:
- A0
- B1
- C2Correct
- Dπ
Correct answer
2
Explanation
∫₀^π sin x dx = [−cos x]₀^π = −cosπ − (−cos0) = 1 + 1 = 2.
Solve this quality-checked NEET multiple-choice question, then review the correct answer and explanation.
∫₀^π sin x dx = [−cos x]₀^π = −cosπ − (−cos0) = 1 + 1 = 2.