Projectile Motion BasicsEasyQuestion 5304
Question
The horizontal range of a projectile is maximum when the angle of projection is:
- A30°
- B45°Correct
- C60°
- D90°
Correct answer
45°
Explanation
R = u²sin2θ/g is maximum when sin2θ = 1, i.e., 2θ = 90°, so θ = 45°.