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Question 5306
NEET Physics · Easy

Motion in a Plane: Projectile Motion Basics MCQ

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Projectile Motion BasicsEasyQuestion 5306

Question

For a projectile launched with speed u at angle θ, the maximum height is:
  1. A
    u²sin²θ/g
  2. B
    u²sin²θ/2g
    Correct
  3. C
    u²sinθ/2g
  4. D
    u²sin2θ/g

Correct answer

u²sin²θ/2g

Explanation

At maximum height, vertical velocity = 0. v² = (usinθ)² − 2gH → H = u²sin²θ/2g.

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