Projectile ApplicationsMediumQuestion 5318
Question
A cricket ball is hit at 45° with velocity 20 m/s. Time of flight (g = 10 m/s²) is:
- A√2 s
- B2√2 sCorrect
- C4 s
- D2 s
Correct answer
2√2 s
Explanation
T = 2usinθ/g = 2×20×(1/√2)/10 = 40/(10√2) = 4/√2 = 2√2 s.