Advanced ProjectileHardQuestion 5341
Question
A projectile is fired at 60° with speed 40 m/s (g=10 m/s²). Time to reach maximum height is:
- A2 s
- B4 s
- C2√3 sCorrect
- D4√3 s
Correct answer
2√3 s
Explanation
t = usinθ/g = 40×sin60°/10 = 40×(√3/2)/10 = 2√3 s.