Moment of InertiaMediumQuestion 6147
Question
MI of thin circular ring (M, R) about axis through centre perpendicular to plane:
- AMR²/2
- BMR²Correct
- C2MR²
- DMR²/4
Correct answer
MR²
Explanation
I_ring (through centre, perpendicular) = MR².
Solve this quality-checked NEET multiple-choice question, then review the correct answer and explanation.
I_ring (through centre, perpendicular) = MR².