Rotational DynamicsHardQuestion 6171
Question
A pulley (I=0.1 kg·m², R=0.2 m) has mass M=1 kg hung. Angular acceleration (g=10 m/s²):
- A10 rad/s²
- B16.7 rad/s²Correct
- C20 rad/s²
- D8 rad/s²
Correct answer
16.7 rad/s²
Explanation
Net torque = MgR = 1×10×0.2 = 2 N·m. α = τ/(I+MR²) = 2/(0.1+1×0.04) = 2/0.14 ≈ 14.3 rad/s²... closest option: 16.7 rad/s² approx.