Rotational KE MixedHardQuestion 6179
Question
A cylinder (I=1 kg·m²) rotating at 10 rad/s is brought to rest in 5 s. Average power dissipated:
- A100 WCorrect
- B10 W
- C50 W
- D200 W
Correct answer
100 W
Explanation
KE = ½×1×100 = 50 J. P_avg = ΔKE/t = 50/5 = 10 W. Hmm: P = 50 J/5 s = 10 W. Correct answer: 10 W.