Moment of Inertia MixedHardQuestion 6195
Question
Two thin rods (each mass M, length L) form '+' shape. MI about axis through centre perpendicular to both:
- AML²/6Correct
- BML²/12
- CML²/3
- D2ML²/3
Correct answer
ML²/6
Explanation
Each rod: I = ML²/12 about its centre (perpendicular axis). Two rods: I_total = 2×ML²/12 = ML²/6.