CollisionsHardQuestion 6068
Question
Ball (m) dropped from H, bounces with e = 0.5. Height of first bounce:
- AH/2
- BH/4Correct
- CH/8
- DH/16
Correct answer
H/4
Explanation
v_after = e√(2gH). h = v²/2g = e²H = 0.25H = H/4.
Solve this quality-checked NEET multiple-choice question, then review the correct answer and explanation.
v_after = e√(2gH). h = v²/2g = e²H = 0.25H = H/4.