CollisionsHardQuestion 6069
Question
Neutron (m) elastically hits carbon nucleus (12m) at rest. Fractional KE loss:
- A48/169Correct
- B12/13
- C1/13
- D144/169
Correct answer
48/169
Explanation
Fractional KE loss = 4Mm/(M+m)² = 4×12/169 = 48/169.
Solve this quality-checked NEET multiple-choice question, then review the correct answer and explanation.
Fractional KE loss = 4Mm/(M+m)² = 4×12/169 = 48/169.