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Question 600414
JEE Chemistry · Hard

Chemical and Ionic Equilibrium: Ksp MCQ

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KspHardQuestion 600414

Question

The solubility product of BaSO₄ (Ksp = 1×10⁻¹⁰) in pure water. The molar solubility s is:
  1. A
    10⁻⁵ M
    Correct
  2. B
    10⁻¹⁰ M
  3. C
    10⁻² M
  4. D
    10⁻⁸ M

Correct answer

10⁻⁵ M

Explanation

BaSO₄ ⇌ Ba²⁺ + SO₄²⁻. Ksp = s² = 10⁻¹⁰. s = √(10⁻¹⁰) = 10⁻⁵ M.

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