Torque MixedHardQuestion 6188
Question
A thin rod (M, L) can rotate about pivot at one end. Horizontal rod released. Angular acceleration at start:
- A3g/2LCorrect
- Bg/L
- C3g/L
- Dg/2L
Correct answer
3g/2L
Explanation
τ = Mg×L/2. I = ML²/3. α = τ/I = (MgL/2)/(ML²/3) = 3g/(2L) = 3g/2L.