Moment of Inertia MixedEasyQuestion 6189
Question
MI of a thin disc (M, R) about axis through centre in plane of disc:
- AMR²
- BMR²/4Correct
- CMR²/2
- D2MR²
Correct answer
MR²/4
Explanation
By perpendicular axis theorem: MR²/2 = 2I_d. I_d = MR²/4.
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By perpendicular axis theorem: MR²/2 = 2I_d. I_d = MR²/4.